If it is 10.00 a.m. I.S.T., then what would be the local time at Shilong on 92°E longitude?

1. The question provides the Indian Standard Time (IST) as 10.00 a.m. and asks for the local time at Shillong, located at 92°E longitude. 2. IST is based on the standard meridian of India, which is 82°30'E (82.5°E). 3. Shillong is located at 92°E longitude. 4. The longitudinal difference between Shillong and the standard meridian is 92°E - 82.5°E = 9.5 degrees. 5. The Earth rotates 360° in 24 hours, which means it rotates 1° in (24 * 60 / 360) = 4 minutes. 6. The time difference corresponding to the 9.5-degree longitudinal difference is 9.5 * 4 minutes = 38 minutes. 7. Since Shillong (92°E) is located to the east of the standard meridian (82.5°E), its local time will be ahead of IST. 8. Therefore, the local time at Shillong will be 10.00 a.m. + 38 minutes = 10.38 a.m.