What is the total number of digits printed, if a book containing 150 pages is to be numbered from 1 to 150?

To solve this, I will break the page numbers into groups based on how many digits they have. This is a standard 'Intuitive Counting' approach [5, 7].\n\n1. **Pages 1 to 9 (Single Digit Numbers):**\n - There are 9 numbers here.\n - Each has 1 digit.\n - Total digits = 9 * 1 = 9.\n\n2. **Pages 10 to 99 (Double Digit Numbers):**\n - Using the inclusive counting principle [1, 31]: Count = (99 - 10) + 1 = 90 numbers.\n - Each has 2 digits.\n - Total digits = 90 * 2 = 180.\n\n3. **Pages 100 to 150 (Triple Digit Numbers):**\n - Here is the potential trap. We need the count from 100 to 150 inclusive.\n - Count = (150 - 100) + 1 = 51 numbers. (Many students might mistakenly guess 50).\n - Each has 3 digits.\n - Total digits = 51 * 3 = 153.\n\n4. **Final Summation [12]:**\n - Total = 9 (from 1-9) + 180 (from 10-99) + 153 (from 100-150).\n - Total = 189 + 153 = 342.\n\nThe logic holds up against the boundary checks, and the calculation is straightforward.