Three persons A, B and C are standing in a queue not necessarily in the same order. There are 4 persons between A and B, and 7 persons between B and C. If there are 11 persons ahead of C and 13 behind A, what could be the minimum number of persons in the queue?
A
(a) 22
B
(b) 28
C
(c) 32
D
(d) 38
Correct Answer: Option A
Explanation
1. **Establish Anchor:** The question says '11 persons ahead of C'. This is our fixed starting point.
- Position of C = 11 + 1 = **12th**. (C is number 12 from the front) [1]
2. **Apply Minimization