The following table shows the marks obtained by two students in different subjects: | | Student A | Maximum Marks | Student B | Maximum Marks | |---|---|---|---|---| | English | 60 | 100 | 80 | 150 | | Psychology | 70 | 100 | 70 | 100 | | History | 50 | 100 | 60 | 100 | | Sanskrit | 30 | 50 | 15 | 25 | The difference in the mean aggregate percentage marks of the students is

To find the difference in performance, I need to calculate the overall percentage for both students.\n\n**Step 1: Student A**\n- Total Marks Obtained: $60 + 70 + 50 + 30 = 210$\n- Total Maximum Marks: $100 + 100 + 100 + 50 = 350$\n- Fraction: $210 / 350$. I can cancel the zero to get $21 / 35$. Both are divisible by 7. $21/7 = 3$, $35/7 = 5$. So, the ratio is **3/5** (which is 60%).\n\n**Step 2: Student B**\n- Total Marks Obtained: $80 + 70 + 60 + 15 = 225$\n- Total Maximum Marks: $150 + 100 + 100 + 25 = 375$\n- Fraction: $225 / 375$. Instead of dividing, I look for common patterns. Both end in 25. \n - $225 = 9 \\times 25$\n - $375 = 15 \\times 25$ \n- This reduces to $9 / 15$. Both are divisible by 3. $9/3 = 3$, $15/3 = 5$. So, the ratio is also **3/5** (which is 60%).\n\n**Step 3: Conclusion**\nSince both students secured an aggregate of 60% (or 3/5 ratio), the difference between them is zero.