The 5-digit number PQRST (all distinct digits) is such that T ≠ 0. P is thrice T. S is greater than Q by 4, while Q is greater than R by 3. How many such 5-digit numbers are possible ?
Correct Answer: Option B
Explanation
1. **Analyze Chain 1 (P, T):**
The rule is $P = 3T$. Since $P$ must be a single digit ($0-9$) and $T \neq 0$:
- If $T=1$, then $P=3$. Pair A: {1, 3}
- If $T=2$, then $P=6$. Pair B: {2, 6}
- If $T=3$, then $P=9$. Pair C: {3, 9}
- ($T=4$ mak
Master UPSC Revision
Get 10,000+ topic-wise MCQs, spaced repetition, daily CSAT challenges, and detailed performance analytics.
Coming Soon to Play Store