A train 200 metres long is moving at the rate of 40 kmph. In how many seconds will it cross a man standing near the railway line?

1. **Identify Goal**: We need to find the time taken for a 200-meter train to cross a standing man. This means the train must travel 200 meters.\n\n2. **Analyze Speed via Proportionality**: The speed is given as 40 kmph. \n - As per the 'Unitary Method' concept in the context [30] [40], we can express this linearly:\n - 40 km are covered in 1 hour.\n - Convert to matching units: 40,000 meters are covered in 3600 seconds.\n\n3. **Apply Scaling**: We need to find the time for **200 meters**.\n - Look at the relationship between 40,000 meters and 200 meters.\n - First, remove two zeros from both sides: 400 meters are covered in 36 seconds.\n - Now, we need 200 meters (which is half of 400 meters).\n - Therefore, the time will be half of 36 seconds.\n - Time = 18 seconds.\n\n4. **Conclusion**: This approach avoids the '5/18' fraction multiplication entirely and relies on the intuitive 'Direct Proportionality' discussed in previous years' analysis [40].\n\nThe calculated time is 18 seconds.