A student has to get 40% marks to pass in an examination. Suppose he gets 30 marks and fails by 30 marks, then what are the maximum marks in the examination?

1. Understand the Passing Requirement: The student got 30 marks and fell short by 30 marks. Using the 'Target-Deficit Analysis' seen in PYQs [11], the passing mark is simply the sum: 30 + 30 = 60 marks.\n\n2. Establish Equivalence: The question states the passing percentage is 40%. Therefore, 40% of the total marks is equal to 60 marks.\n\n3. Scale to find Total (Maximum Marks): We need to find 100%. Instead of dividing 60 by 0.4, we can use the 'Linear Scaling' method [46] observed in the 2014 loan question:\n - If 40% = 60 marks, then half of that, 20%, must be 30 marks.\n - Since 100% is five times 20%, the total marks are 30 * 5 = 150 marks.\n - This is the same 'Unitary Method' logic required to solve the 2014 bus fare question [14].\n\n4. Conclusion: The maximum marks are 150.